3a^2/4+2ab/3+ab-a^2
What would you like to do?
Simplify the equation.
ok, so we have \[\frac{3a^2}{4}+\frac{2ab}{3}+ab-a^2\] carrect?
Yes.
So, first, can you tell me what the like terms are?
3a^2 & -a^2, 2ab & ab.
ok, now you left out the denominators of the coefficients, was that intentional?
No.
ok, so I think that is where your problem is. You did very well at identifying the like terms, but you cannot forget the denominators in this case. Since multiplication is commutative, you can write 3a^2/4 a few different ways. \[\frac{3a^2}{4}=\frac{3}{4}a^2=\frac{1}{4}3a^2=3\frac{a^2}{4}\]
those are all equivalent statements, so when you combine your like erms, you have to remember the whole coefficient, not just the numerator
also(there should be parentheses around one of those to show multiplication up ther like this ) \[(\frac{3a^2}{4})=(\frac{3}{4})a^2=(\frac{1}{4})3a^2=3(\frac{a^2}{4})\]
Ok.
so, can you combine your like terms for me now?
If I combine like terms, would my equation then be: 2a^2/4+3ab/3?
well, how did you combine the 3a^2/4 & -a^2?
I have no idea, I'm extremely confused.
ok, so if you had \(\frac{3}{4}+(-1)\) what would you do?
-1/4
good! so it is the exact same here
ACTUALLY, a really cool thing \[\frac{3a^2}{4}-a^2=(\frac{3}{4}-1)a^2\] It is called the distributive property
That makes sense!
yup yup, so now, can you combine the ab terms?
(2ab/3+ab)= (2/3+1)ab?
yep
once you hit a certain level, we tend to forget when we explain that this is really what we are doing. We skip steps so much that we forget they exist
Thanks for your help, it was greatly appreciated!
np, just remember it is the commutativity of addition and the distributive property that allows you to do these things like grouping your like terms and factoring
medal pwease?
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