What is the mass defect (in kg), if a 40 over 20 Ca has an expected mass of 40.3313 amu and an actual mass of 39.9626 amu? 1 amu = 1.66 × 10-27 kg Answer 0.369 kg 6.12 × 10-28 kg 80.3 kg 1.33 × 10-25 kg
http://www.chem.purdue.edu/gchelp/howtosolveit/Nuclear/nuclear_binding_energy.htm The first section shows how to calculate mass defect. :)
uhh that site doesnt come up for me?
It' the same thing...u have to use \(E=mc^2\)
so how do i set it up
you should really check the article @JoannaBlackwelder just gave u....that can make u understand better
yeah im sure it will, except the fact that it will not load and im getting a 404 error
Here is the main part of how to calculate. To calculate the mass defect: add up the masses of each proton and of each neutron that make up the nucleus, subtract the actual mass of the nucleus from the combined mass of the components to obtain the mass defect.
use this
There you go. Can you read it on that document?
Good idea, @Abhisar :)
im doing it wrong because every time i do it im getting a number not in my options. damn i hate everything that has to do with chemistry
Once you get an answer in amu, did you convert to kg?
Also, how many protons and how many neutrons did you get?
yes haha
:)
What was the number of protons and the number of neutrons you got?
already got rid of it but i know it was wrong XD
When you have |dw:1408851351226:dw| the 40 is the sum of protons and neutrons and the 20 is the number of protons.
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