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Prove that if mn is odd, then both m and n are odd.
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Hint :- odd formula 2n+1
Because any odd number multiplied by a multiple of two is even.
so assume m=2k+1 n=2g+1 mn=(2k+1)(2g+1)=(4kg+2k+2g+1)=2(2kg+k+g)+1=2n+1
I think you are proving it the other way. The question starts off with mn being odd
No, I'm showing why neither number can be even :) If the product is odd, you \(cannot\) have an even integer in the equation.
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DangerousJesse: I understand what you are saying, but how can we show this as a mathematical proof? :)
I'm not sure I understand you?
Oh!
God, I'm being so dense -.- My apologies.
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