Write the equation of a line that passes through the point (-1,3) and is perpendicular to the line y=3
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OpenStudy (anonymous):
what is the relationship with perpendicular lines and their slopes?
OpenStudy (anonymous):
the slopes are recipricol
OpenStudy (anonymous):
negative reciprocals.
OpenStudy (anonymous):
so you are given y = 3..the slope is ??
OpenStudy (anonymous):
-1/3
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OpenStudy (anonymous):
y = mx + b
slope is M
OpenStudy (anonymous):
so try it again, what is the slope of y = 3
OpenStudy (anonymous):
-1/3
OpenStudy (anonymous):
no the slope is 0.. think of this way - slopes are coefficients of the x variable when the y variable has a 1 in front of it.
OpenStudy (anonymous):
oh ok
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OpenStudy (anonymous):
so negative recip of 0 is 0
so with that information..use the point given (-1,3) to find the new equation
y - y1 = m (x - x1)
remember we just determined that M = 0
OpenStudy (anonymous):
so what is the new line?
OpenStudy (anonymous):
this is probably wrong but...y-3=x+1
OpenStudy (anonymous):
close :) you forgot the M
OpenStudy (anonymous):
y - 3 = 0 (x +1)
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OpenStudy (anonymous):
and the final answer is where Y is on the side by itself..
OpenStudy (anonymous):
y=x-2?
OpenStudy (anonymous):
y=x+4
OpenStudy (anonymous):
actually, y = 3
OpenStudy (anonymous):
looks like you are not distributing properly...zero times a number is what?
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OpenStudy (anonymous):
0
OpenStudy (anonymous):
exactly :)
OpenStudy (anonymous):
You good on this now?
OpenStudy (anonymous):
ok thanks again!
OpenStudy (anonymous):
No problem...I like helping you understand versus just wanting an answer. happy studying