Question

Horizontal asymptote help!

I got no horizontal asymptotes for both, but I think that's wrong.

State the horizontal asymptote of the rational function.

f(x) = (x^2 + 6x - 8) / (x - 8)

and

f(x) = (x^2 + 3x - 2) / (x - 2)

Answer 1

the first: y=x+8
i'm doing the second, do u wonna the passages?

Answer 2

sorry y=x+6

Answer 3

So the horizontal asymptote really isn't zero, right? I got zero, but I have a feeling it's wrong.

Answer 4

just a second, i'm checking out the calculus ;)

Answer 5

Ok! thx

Answer 6

Ok the first is : y=x+14 (for sure xD)

Answer 7

Ok great

Answer 8

Could you show me how you got that answer, if you have the time :)

Answer 9

I should have got the time, butt someone enjoyed in suspending me because I didn't give you the explanation (actually I was typing it) :)

Answer 10

\[m=limx-->\inf (fx/x)\]
and that equals one

Answer 11

Then, \[q=limx-->\inf(fx-mx)\]
and that equals 14
So
y=x+14
If you haven't got with the limits tell me ;)

Answer 12

The other one is the same method of course, it gives me y=x+5
The same, tell me if you have problem with calculus ;)
****PLEASE DO NOT SUSPEND ME I GAVE THE FOURMULA AND EXPLANATION ABOVE****

Answer 13

Thank you for your time and sorry for the trouble!

Answer 14

Don't worry it's not your fault :)