A regular octagon has perimeter of 87.2 in and the area is 573.67 in2. A second octagon has an area equal to 2294.66 in2. Find the perimeter of the second octagon. Round to the nearest hundredth

Question

anonymous · Answer

All regular $n$-gons are similar to other regular $n$-gons. This means you can set up a ratio due to the similarity:
$$\frac{\text{area}}{\text{perimeter}}=\frac{573.67}{87.2}=\frac{2294.66}{x}$$
Solve for $x$, which is the perimeter of the second octagon.

anonymous · Answer

Thank you