Question

dentify the outlier in each data set. Th en fi nd the mean, median, and mode of the data set when the outlier is included and when it is not. 16. 947 757 103 619 661 582 626 900 869 728 1001 596 515 @amistre64

Answer 1

youre gonna want to sort the set to start off with

Answer 2

there are 13 numbers

Answer 3

we are not really asked for positions here; so you will have to know the definitions of the words they use

Answer 4

the outlier is the largest number

Answer 5

mode is number used most often, median is a postion ... the number in the middle of it all, and mean is a mathical calulation

an outlier is not really the largest number, its more of a number that doesnt seem to fit in; it can be large or small, but it just doesnt seem to fit in with the rest

Answer 6

so 16

Answer 7

is 16 part of the data set, or is that just eh number of the problem you are doing?

Answer 8

well i gues its 103 because i dont think 16 is in there

Answer 9

yeah my bad....i dont think 16 is supposed to be there lol

Answer 10

{103, 515, 582, 596, 619, 626, 661, 728, 757, 869, 900, 947, 1001}

103 seems to be a bad fit, i agree

1001 seems to be about 50 away, and there are others that are about 50 apart so i would say that one is not an outlier.

Answer 11

none of the numbers are used more than once, so we say there is no mode.

Answer 12

13 numbers, so the median is the 13/2 = 6.5, rnd up ... the 7th number

Answer 13

this is assuming we havent removed the outlier yet

Answer 14

whats the 7th number

Answer 15

i posted a sorted list ....

Answer 16

oh lol i see that

Answer 17

is that it?

Answer 18

thats a part of what the question is asking for

it wants you to determine an outlier: 103

and find the mean, mode, median of the set both with and without the outlier included

Answer 19

the median changes, the mode does not since none of the numbers are used more than once, and the mean will change as well

Answer 20

i have the median thats it

Answer 21

you also have the mode and outlier

Answer 22

and outlier. wheres the mode

Answer 23

nevermind

Answer 24

okay so whats the mean

Answer 25

the mean is a calculation, sum up the numbers in the data set, and divide by how many there are

Answer 26

\[A = \{a_1,a_2,...,a_n\}\]
\[mean~of~A=\frac{a_1+a_2+...+a_n}{n}\]

Answer 27

well i know the definition lol

Answer 28

got it thank you

Answer 29

now remove the outlier and the median changes, and the mean changes

Answer 30

i didnt include them

Answer 31

i will have more questions tomorrow

Answer 32

good luck :) im not always here, but there should be someone around that can help