A system of equations is shown below: -3x + 7y = -16 -9x + 5y = 16 Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this. (6 points) Part B: Show that the equivalent system has the same solution as the original system of equations. (4 points)
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Part A: I replace 2nd equation with sum of 1st and 2nd equation so I get system: -3x + 7y = -16 -12x + 12y = 0
Part B - You must solve original system of equation; you will get solution: x = -4 y = -4 And then substitute this solution into equivalent system of equation: -3*(-4) + 7*(-4) = -16 -12*(-4) + 12*(-4) = 0 And evaluate expressions to prove that equivalent system of equation have same solution.
OMFG TY TY TY TY
is this the final answer for B? @triangleguru ?
B - I think thats final solution. In A part I constructed replaced equation sa B = 1*A+B. So multiple coeficient was "1". If you choose B = 2*A+B, you will get equivalent system: -3x + 7y = -16 -15x + 19y = -16
okay TY SO VERY MUCH!!! no one else was helping me i been on this question 2h plus
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