Lineintegrals and double integrals: f(x,y)=x^2y+yx for (x,y) element of R, where R is the region between y=0, x=4 and y=x. Evaluate integral with the limits of R f(x,y) dS. I'm suspecting I'll have to convert this into a double integral, but not sure what to do with the given function and not sure about the limits either
Do I apply Green on the equation?
show your attempt (sketch the region atleast) its hard to get hang of problem just by reading it once :S
I haven't sketched the function, but I have a sketch of the region in pencil |dw:1409071657413:dw|
So basically you want to evaluate the double integral of f(x,y) in the above region. Is that correct ?
\[\large \iint_R ( x^2y+yx) dxdy\]
I think I have to apply Green's theorem on the function to make it into a double integral. I can do that because the region is closed loop.
Green's theorem is used to compute \(\text{work}\) done along a closed loop. What exactly are you trying to do here ? question did not give any vector field or it was not even asking for work :/
It would be helpful if you can take a snapshot of actual question and attach
\[\int\limits_{R}^{}f(x,y) dS=\int\limits_{R}^{}x^2y dx+yx dy\] Green is for vector fields, not necessarily work. I don't think a snapshot will be of any help, unless you can read Dutch. No drawings. But the b) part of the question says: what would happen if you change the integration order around? Which can only mean getting a double integral. The exercise sheets are about line integrals and double integrals. Surface/Area integrals is the next sheet. The region is closed and can be seen as a closed field.
you're not given any vector field here, so it makes no sense to talk about work or green's theorem here
The integral would become \[\int\limits_{}^{} \int\limits_{D}^{}(2xy-x) dx dy\]
what you're given is a function of two variables f(x,y) and a region to integrate over, so all you need to is to integrate. thats all i think
a part question is evaluate \[\int\limits_{R}^{}f(x,y) dS\]
strictly speaking, it should be asked as : \(\large \iint\limits_R f(x,y) dS\)
Well, that's the problem: that's not what the exercise sheet says.
region => doible integral path => line integral space => triple integral
Then they must have made a typo or something
possible, did you get why this is not a `work/flux/green's theroem` problem ?
Yes
why ?
It wasn't said it's a vector field
exactly ! vector field requires two components : F = <M, N> but in your question there is no vector field, so you shouldn't even think about `work/green's theorem` here
|dw:1409072790664:dw|
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