Determine whether the graphs of these equations are parallel, perpendicular, or neither; with explanation please. 1. y = 4x + 5 -4x + y = -13 2. y = 7/8 x = -4 3. 3x + 6y = 12 y-4=-1/2(x+2)
Parallel lines have the same coefficients for x's and y's, they differ on constant terms such that... line 1: \(A_1x+B_1y=C_1\) line 2: \(A_2x+B_2y=C_2\) and \(A_1=A_2\) as well as \(B_1=B_2\), but \(C_1\ne C_2\)...also the slopes \(m_1=m_2\).
Perpendicular lines have an interchanged coefficients for x's and y's such that... line 1: \(Ax+By=C_1\) line 2: \(Bx+Ay=C_2\) ... also their slopes are negative reciprocal of one another such as \[m_1=-\frac{1}{m_2}\] Another case is the vertical line \((x=A)\) and a horizontal line \((y=B)\), obviously they are perpendicular to each other.
If neither the case of parallel lines nor perpendicular lines are met, then it's neither parallel nor perpendicular.... Hope this will help you answer your problems from 1 to 3. \(\ddot\smile\)
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