@ShadowLegendX

Question

@ShadowLegendX

shadowlegendx · Answer

Yes?

anonymous · Answer

Solve. $$\log_{2} \left( 3-7x \right) = \log_{2} \left( 6x ^{2} \right)$$

anonymous · Answer

@prowrestler :

IS THE ANSWER IS:
$$x = -\frac{ 3 }{ 2 } =1.5000$$
and 
$$x \approx 0$$
?

anonymous · Answer

are you asking me if that's the answer

anonymous · Answer

yes

anonymous · Answer

I don't know that's why I posted it

anonymous · Answer

typo there x =0.3333..

anonymous · Answer

I'm asking for the answer given in the back page of the book

anonymous · Answer

its an online class

anonymous · Answer

there should be a 'SHow Aswer' or 'Hint' button I lost the track of calculation I guess

anonymous · Answer

do you have a more advanced calculator

anonymous · Answer

nah. see

..
see you know that log can be written in exponential form to so from the above statement we can reqwrite it as:
$$[2^{\log_{2} 6x^2 } = 3-7x$$\]

anonymous · Answer

or 

$$2^{\log_{2} (3-7x)} = 6x^2$$

..now something ticked in your mind?

anonymous · Answer

so what would the answer be

anonymous · Answer

my guesses are that 

x = -3/2 = 1.5000(approx)
x= 1/3 = 0.3333

let me check it out with wolfram....I guess it will be able to compute the right answer ..

wait a min...

anonymous · Answer

oh yes... http://www.wolframalpha.com/input/?i=Solve+log2%283%E2%88%927x%29%3Dlog2%286x2%29 Wolfram also simplified the answer and expressed it in log way rather than the complex exponential way of mine...