Chemistry
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OpenStudy (asib1214):
what volume of hydrogen gas at STP will be produced when 1000g of aluminum is added to 4.00L of 1.40mol/L Sulfuric acid? @abb0t
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OpenStudy (asib1214):
@aaronq
OpenStudy (aaronq):
so you got the balanced equation?
OpenStudy (asib1214):
2Al + 6HCl ---> 2AlCl3 + 3H2
OpenStudy (aaronq):
okay now, find the limiting reagent. we divide the moles of each of the reactants by their stoichiometric coefficient and see which one has less.
OpenStudy (asib1214):
ok please wait let me do that step
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OpenStudy (aaronq):
okay
OpenStudy (asib1214):
sorry it's not coming to mind :(
please give me a clue :(
OpenStudy (aaronq):
okay, so for the aluminum, you wanna find the moles from the mass.
\(\sf moles=\dfrac{mass}{Molar~mass}\)
OpenStudy (asib1214):
yah but we is the mass?
OpenStudy (aaronq):
For the sulfuric acid, you need the moles from the molarity and the volume
\(\sf Molarity=\dfrac{moles}{L}\)
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OpenStudy (asib1214):
we don't have the mass given in this question
OpenStudy (aaronq):
1000g of aluminum
OpenStudy (asib1214):
ok thanks...
OpenStudy (asib1214):
so would it be 1000g/36.46 = 27.42mol
OpenStudy (asib1214):
of cl2
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OpenStudy (aaronq):
now find the moles of sulfuric acid
OpenStudy (aaronq):
that should've been aluminium
OpenStudy (asib1214):
oh sorry...
OpenStudy (asib1214):
yah aluminum
OpenStudy (asib1214):
yah but i don't have the mount of Cl2
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OpenStudy (asib1214):
in grams
OpenStudy (aaronq):
It's not even asking for \(Cl_2\)
OpenStudy (aaronq):
it's not in the question
OpenStudy (asib1214):
sorry its 5.6 mol
OpenStudy (asib1214):
sorry i mean sulfuric acid :(
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OpenStudy (asib1214):
i'm having a really bad day :'(
OpenStudy (aaronq):
okay, divide each by their coefficients
OpenStudy (aaronq):
aw sorry to hear that
OpenStudy (asib1214):
|dw:1409208123034:dw|