Question

A 50.0 g ball of copper has a net charge of 2.3 µC. What fraction of the copper's electrons have been removed? (Each copper atom has 29 protons, and copper has an atomic mass of 63.5.)

Answer 1

Find moles, then atoms of copper.

\(\sf moles=\dfrac{mass}{Atomic ~mass}\)


\(\sf atoms = moles*Avogadro's ~number\)


Find electrons lost by dividing the charge by the charge of the electron \(1.6*10^{-19}~C\)

Find the fraction.