A 50.0 g ball of copper has a net charge of 2.3 µC. What fraction of the copper's electrons have been removed? (Each copper atom has 29 protons, and copper has an atomic mass of 63.5.)

Question

aaronq · Answer

Find moles, then atoms of copper.

$\sf moles=\dfrac{mass}{Atomic ~mass}$


$\sf atoms = moles*Avogadro's ~number$


Find electrons lost by dividing the charge by the charge of the electron $1.6*10^{-19}~C$

Find the fraction.