Question

Any one good at titration?
If 0.4905 g of pure KHP solid were titrated with NaOH and the endpoint was reached at 28.08 mL, what is the concentration of the NaOH solution? (Note: MW of KHP = 204.223 g/mol).

Answer 1

You need the balanced equation, do you have that?

Answer 2

Feel like looking over my work when you get the chance? =)
\[.4905g*\frac{ 1mol }{204.223g }=.0024mol\]
\[28.08ml*\frac{ 1L }{ 1000ml }=.028L\]
\[\frac{ .0024 }{ .028 }=.00857M\]

Answer 3

No equation was provided.

Answer 4

@aaronq

Answer 5

yeah it's right, good job!

Answer 6

thank you