An object is moving from point A to point B. At point A, the time t = 0 s, velocity v = 0 m/s, total force acting on the object F = 6000 N. by the time it reaches point B, velocity v = 4.95 m/s, total force F = 0 N. the equation for F is F = T - D, where T = const = 6000N and D = y * v^2, where y = 245 kg/m. Mass of the object is 300 kg. My problems are, how long does it takes for the object to move from point A to point B and what is the distance covered by the object (time, t at point B and distance from point A to B)?

Question

anonymous · Answer

y= 244.8729721 (to get D = T).
Get total F (integral of its equation)
$$F _{total} = 6000 v - 81.6667 v ^{3}.(from 0 \to 4.95)$$
$$F _{total} = 19794.86437$$
$$dt = \frac{ M dv }{ F _{total} }$$
dt = very small and this make sense 
from kinetic energy equation you can get work
$$0.5Mv _{2} ^{2} - 0.5 M v _{2} ^{1} = W$$
thus W = 7350.75
so dx  = W/F = 0.371346318 m.
and it is done :D

anonymous · Answer

i use y = 245 but i think it is wrong