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Mathematics 11 Online
OpenStudy (anonymous):

A multiple-choice test consists of 9 questions. Each question has answer choices of a, b, c, d, and e, and only one of the choices is correct. If a student randomly guesses on each question, what is the probability that she gets fewer than 2 of them correct? Carry your intermediate computations to at least four decimal places, and round your answer to at least two decimal places.

OpenStudy (anonymous):

Ok, so with the choices of: a, b, c, d, and e, We have a total of 5 solutions to choose from. How many questions does she randomly choose on? That's important to know.

OpenStudy (anonymous):

Because for each question she will have a 1/5 chance of randomly selecting the right answer. This is 20%.

OpenStudy (anonymous):

She randomly guesses on all 9 questions

OpenStudy (anonymous):

So I know that probability states she will get 20% of the questions correct, but I don't know how to calculate the probability of her getting less than 2 questions correct?

OpenStudy (anonymous):

For each question she has 20% likelyhood to get it right. Since there are 9 questions, she has 9 tries of 20% to get right answers. This is shown by multiplying 20% times 9. 20% as a decimal is 0.20, So 0.20 x 9 = (Your answer)

OpenStudy (anonymous):

I think that just tells me how many she will likely get correct.. I need the probability of her getting less than 2 answers correct.

OpenStudy (anonymous):

Well she will get 1.8 (less than two) right, if she randomly guesses on all of the nine, so I would say, since this is less than two, that it is 100% likely she will get less than two right after randomly choosing at a 20% rate 9 times. Does that make sense?

OpenStudy (anonymous):

oh.. yes that does. thank you!

OpenStudy (anonymous):

Awesome, np.

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