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A normal distribution has a mean of 100 and a standard deviation of 12. Find the probability that a value selected at random is in the following interval. At least 76
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@triciaal can you help me out with this one?
sorry not that fast with stats
@campbell_st @Whitemonsterbunny17 @Squirrels do you mind helping?
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\[P(X \ge 76)=P\left(\frac{X-100}{12}\ge\frac{76-100}{12}\right)=P(Z\ge -2) \]And this value you can find using a normal distribution table, a calculator/software , or by using the empirical rule (a.k.a. the 68–95–99.7 rule; knowing that __% of normally distributed date lies within 2 standard deviations of the mean).
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