Question

Please help me? :3

Answer 1

ok so im guessing this wants you to write a y=mx+b kinda thing

Answer 2

we have 2 points

Answer 3

(5,60) and (10,40)

Answer 4

oh so then do i use the formula to find slope?

Answer 5

yes

Answer 6

\[\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} } ?\]

Answer 7

\[\frac{ \Delta f(x)\ }{ \Delta x }\]

Answer 8

yes

Answer 9

\[\frac{40-60}{10-5 }?\]

Answer 10

yep

Answer 11

so then \[\frac{ -20 }{ 5 }\]

Answer 12

\[y=-4x+b\]

Answer 13

and then -4 is the answer YES

Answer 14

there are 2 -4 answers

Answer 15

but it needs to be a function

Answer 16

so now plug in the values for x and y

Answer 17

\[60=-4(5)+b\]

Answer 18

uhh which values? there are 2 that I can use

Answer 19

either of the 2 should work

Answer 20

In y = mx + b

M is the slope, B is the y-intercept or starting point.

1) Obviously it's decreasing, therefore your slope is going to be negative. So that narrows it down to 2 choices.

In week 5 you had 60, therefore by applying the slope formula you'll find that the starting point was 80.


If you wanted to solve it completely,

(5, 60) and (10, 40)

\(\ \sf \dfrac{40 - 60}{10-5} = -20/5 = -4 \)

y - 60 = -4(x - 5)

y - 60 = -4x + 20
+60 +60

y = -4x + 80

Answer 21

ok so uhh 40=-4(10) + b ?

Answer 22

yes that could work

Answer 23

ok so b would be 80??

Answer 24

so then the equation would be y = -4x + 80

Answer 25

but it needs to be a function

Answer 26

now im confused

Answer 27

you could do y=mx+b then plug in one of the (x,y) points for x and y.

or you can do the same thing but say

\[y-y_{0}=-4(x-x_{o})\]

y - 60 = -4(x - 5)

y - 60 = -4x + 20
+60 +60

y = -4x + 80

like fizic did

Answer 28

the function is just f(x)=-4x+80

Answer 29

y=f(x)

Answer 30

ok THANKS!!!

Answer 31

so the answer is D rigth?

Answer 32

could be :)

Answer 33

is that your final answer?

Answer 34

you have 3 life lines left

Answer 35

Yes it is :)

Answer 36

correct

Answer 37

yesss THanks SOOOO much!!

Answer 38

can you help me with one more?

Answer 39

actually nvrminf