Question

help me PLEASE!

Answer 1

idont get it ...
i just know to multiply the first one to the reciprical second one

Answer 2

sooo i get \[\frac{ (3y-9)(15x+90) }{ (x+6)(y-3) }\]

Answer 3

would this be the answer ???? \[\frac{ (45xy-270y-135x-810 }{ (x+6)(y-3) }\]

Answer 4

@jim_thompson5910 @Destinymasha Hello there i was wondering if you can help me confirm my steps to my answer because i am not complete sure about the process

Answer 5

Well the problem is that you are given an equation and not an expression. Are you supposed to solve for x,y,n or d?

Answer 6

i am suppose to find n and d @jim_thompson5910

Answer 7

ok, the first step is to flip the second fraction on the left side and then multiply

Answer 8

yes i got \[\frac{ (3y-9)(15x+90) }{ (x+6)(y-3) }\] @jim_thompson5910

Answer 9

That is incorrect

Answer 10

really .... awww ok let me see what i did

Answer 11

we have this

\[\Large \frac{3}{x+6} \div \frac{y-3}{15} = \frac{n}{d}\]

Answer 12

then we flip that second fraction to get this

\[\Large \frac{3}{x+6} * \frac{15}{y-3} = \frac{n}{d}\]

Answer 13

Then you just multiply straight across

\[\Large \frac{3*5}{(x+6)*(y-3)} = \frac{n}{d}\]

\[\Large \frac{15}{(x+6)*(y-3)} = \frac{n}{d}\]

and optionally you can expand out (x+6)(y-3) to get xy-3x+6y-18

\[\Large \frac{15}{xy-3x+6y-18} = \frac{n}{d}\]

Answer 14

wait how did 3 and 15 turn to 15 ???

Answer 15

oh my bad lol

Answer 16

I had 3*5 instead of 3*15

Answer 17

so 45 goes up top

Answer 18

oh ok n_n

Answer 19

then my problem was just i over think it and it was simply to multiply across .... thank you

Answer 20

you're welcome