Question

Find the derivative : (problem is in the comments section)

Answer 1

\[y=\(x^\2\ \-\ \5x \+\ \4\)e^\3x\]

Answer 2

hmmm what is that?

Answer 3

use the drawing box

Answer 4

Wait, something's wrong with the equation maker. :/

Answer 5

haha lol use the drawing tool

Answer 6

y=(x^2 -5x + 4)e^3x

Answer 7

Is this ok? Haha

Answer 8

yeah pretty good^_^

Answer 9

use the product rule and then chain rule

Answer 10

Wait, I'll try, and then tell me if it's wrong. :)

Answer 11

\((f.g)'=f'g+g'f\)

Answer 12

yeah! try^_^

Answer 13

y = (x^2 -5x + 4)(3e^2x) + (2x - 5)(e^3x)

Answer 14

How's that?

Answer 15

Is it just mine, or you got the math processing error too? lol

Answer 16

well the last term you got it right! good on that part
the first one you got the derivative of \(e^{3x}\) wrong

Answer 17

no it seems fine to me

Answer 18

Oh sorry I meant 3x, still right?

Answer 19

yes good job

Answer 20

I refreshed the page, it's fine now. Haha

Answer 21

So, is that the final answer already?

Answer 22

now just factor e^3x to make it look nice

Answer 23

i would always go with simplifying some terms if possible
that by factoring. so the final answer should be clean haha

Answer 24

\[y=e^3x (x^2-5x+4)(3) + (2x-5)\]

Answer 25

Is that right? Haha. And if it is, I'd multiply 3 to the 1st one right? Then, I'd add the second one to it?

Answer 26

that doesn't look nice hehe.

Answer 27

where that x came from

Answer 28

put curly braces around {3x} if you want \(\Large e^{3x}\) or else you will get \(\Large e^3x\).

Answer 29

The x is an exponent it wont come up. lol

Answer 30

Ooh. Thanks! @aum

Answer 31

oh i see so it is the equation tool

Answer 32

You are welcome.

Answer 33

do it like this `\(\large e^{3x}[3(x^2-5x+4)+(2x-5)]\)`

Answer 34

\(\large e^{3x}[3(x^2-5x+4)+(2x-5)]\)

Answer 35

i'm not too good in latex as well haha

Answer 36

So is the final answer \[e^{3x}(3x^2-13x+7)\]

Answer 37

aum how to you do this