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Mathematics 13 Online
OpenStudy (anonymous):

please help with number 9 and 10?

OpenStudy (anonymous):

OpenStudy (anonymous):

I think number 9 is 11,200 and I think 10 is in 2 days from day 3 but i'm not sure

OpenStudy (aum):

That is correct for #9 although it would be nice if the work is shown.

OpenStudy (aum):

For 12, it might be easier to simply extend the table. You already did altitude at end of day #4 to be 11,200 ft. What is the altitude at the end of day #5? Will the peak have been reached by then? Can the peak be reached on day #6? Can the peak ever be reached? A slightly longer method might be as follows: The distance climbed each day is an arithmetic sequence with first term \(a_1=4,000\) and common difference \(d=−800\). Use the formula for the sum of the first n terms of an arithmetic sequence to find n. \[ S_n = \frac n 2 \{2a_1 + (n-1)d\} \ge 12,388 \\ \frac n2\{ 2*4000 + (n-1)(-800)\} \ge 12,388 \]Solve for n. Does a solution exist?

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