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Chemistry 14 Online
OpenStudy (anonymous):

Which of this will split into two organic compounds, both containing a ketone group, when treated with hot acidified potassium manganate(VII) ?

OpenStudy (anonymous):

OpenStudy (abmon98):

In the case if you have two identical molecule, you would end up with two organic compounds both containing a ketone group. |dw:1409369672518:dw|

OpenStudy (abmon98):

If there are two alkyl groups at one end of the bond, that part of the molecule will give a ketone. If there is one alkyl group and one hydrogen at one end of the bond, that part of the molecule will give a carboxylic acid. If there are two hydrogens at one end of the bond, that part of the molecule will give carbon dioxide and water.

OpenStudy (anonymous):

why is 3 incorrect?

OpenStudy (abmon98):

3- the compound is not symmetrical.

OpenStudy (anonymous):

meaning ?

OpenStudy (abmon98):

if you have a look at the structure of 1) you would realize that the compound is identical.

OpenStudy (abmon98):

in 1) you can easily split the double bond of compound apart and replace it with the Carbon-oxygen double bond.

OpenStudy (abmon98):

you cannot split 3 into two similar ones

OpenStudy (abmon98):

|dw:1409370857288:dw|

OpenStudy (anonymous):

i get it now :) thanks!

OpenStudy (abmon98):

good to hear that, yw :D

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