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How do you solve: radical 49/8 < is in fraction form. How do you get the answer?
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\[\sqrt{\frac{ 49 }{ 8 }}\] is the same as \[\frac{ \sqrt{49} }{ \sqrt{8} } \]
@babaloo i know that part but what do i do next
\[\frac{ 7 }{ \sqrt{8} }\]
\[\sqrt{8}=2\sqrt{2}\]
\[\frac{ 7 }{ 2\sqrt{2} }\] yess?
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@kkutie7 the calculator gave me a different answer: 7radical 2 /4 idk how it got it.
Many books and teachers do not like radicals in the denominator and so you need to get rid of it by "rationalizing the denominator". Multiply top and bottom by sqrt(2): \[ \large \sqrt{\frac{49}{8}} = \frac{7}{\sqrt{4\times 2}} = \frac{7}{2\sqrt{2}} = \frac{7}{2\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}} = \frac{7\sqrt{2}}{2*2} = \frac{7\sqrt{2}}{4} \]
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