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OpenStudy (perl):

physics gravity question

OpenStudy (perl):

Prove that bodies accelerate (due to gravity) at a constant rate which we will call 'g'.

OpenStudy (perl):

Now we can do an empirical proof, do an experiment outside and drop balls

OpenStudy (anonymous):

we need heavy objects not effected by air resistence.

OpenStudy (perl):

We can use a photographic still camera (and measure the frames, etc ). But it is interesting that 'g' can be derived from newtons 2nd law and newtons law of universal gravitation.

OpenStudy (perl):

THis is what i mean about what's 'important'. THese two laws are very important. ok lets do a review

OpenStudy (perl):

2nd law of newton. anytime an object undergoes an acceleration, there is a force. THe acceleration is proportional to the force (more force more acceleration), and inversely proportional to mass (more mass less acceleration).

OpenStudy (perl):

a = F / m

OpenStudy (anonymous):

right

OpenStudy (perl):

newtons universal law of gravitation: newton found a formula that related two masses , he posited there is always a force of attraction between two masses. the force between two masses ; F = G*M*m/R^2

OpenStudy (perl):

you could say the force is proportional to the product of the masses and inversely proportional the square of the distance. thats where the G comes in (constant of proportionality)

OpenStudy (perl):

ok so far?

OpenStudy (anonymous):

I know all this :)

OpenStudy (perl):

so we have two equations so far F = m*a F = GM*m/R^2

OpenStudy (perl):

ok at the surface of earth we have m*a = GM*m/R^2 ,

OpenStudy (anonymous):

it is similar for an electric charge among 2 charges

OpenStudy (perl):

so a = GM/R^2 (canceling the m's)

OpenStudy (perl):

these are all constants, G is universal constant of gravity, M is mass of earth, R is radius of earth

OpenStudy (perl):

so we just call this 'g' , g = GM/R^2

OpenStudy (perl):

it comes out to be about 9.8 m/s^2

OpenStudy (perl):

now lets derive an equation for force at height x above the surface of the earth

OpenStudy (perl):

err, i mean acceleration .

OpenStudy (perl):

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OpenStudy (perl):

can you find a general formula for acceleration?

OpenStudy (perl):

@timo86m , at a height x(t) , what is the acceleration due to gravity . we can assume that the object is at some height above the surface of the earth at time t

OpenStudy (anonymous):

earth is so big u can safely assume that 10 m/s^2 at any height.

OpenStudy (perl):

not for rockets or spaceships

OpenStudy (anonymous):

unless you shooting a precision rocket.

OpenStudy (perl):

its really easy, i will show you

OpenStudy (anonymous):

there is a map on my txt book for all the Gs on earth.

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