Question

Write and balance the following chemical equations:
iron(III) chloride+ hydrochloric acid ->_________

Answer 1

Iron(III) chloride and hydrochloric acid do not react.

Answer 2

I think it would be best if you explained to the user WHY they would not react. That might help understand the concept.

Answer 3

If the user is interested in why, s/he'll ask. It seems more likely it's just a matter of getting some homework done.

Answer 4

Sorry, I wasn't in the room and I just saw this. I really don't know how to do this. It's one of the questions for my homework but since you said that it doesn't react, can you tell me why?

Answer 5

Which is WHY they should know. If it's homework, don't you think it's important they understand so they're prepared for the exam ? Herp-derp!

Answer 6

Yeah, I've been having a hard time with these types of chemical equations. I know how to balance them and everything but I don't know what type of reaction each one is. I thought that maybe it would be double replacement but then I would be getting the same thing on both sides.

Answer 7

I think that if they don't ask, they will ignore all the "explanation".

Answer 8

There is not reaction because both "reactants" contain a common ion, namely Cl{-}.
Since they start out with the same anions, there is no kind of rearrangement of ions that could produce anything different that what you had at the beginning.

Answer 9

Ahh. Okay then. So when ever there is a common ion it doesn't change?

Answer 10

Yes.
It works the other way too: There's no reaction between NaCl and NaNO3 for the same reason, except in this case the common ions are cations.

Answer 11

Ahhh. Okay then. Thank you so much!! I get it now. I was struggling with this question for days and now it's all cleared up. Thanks!!

Answer 12

Ohh wait. I have a question.. when writing the equation does the order of the compounds/elements matter?

Answer 13

No. It matters a lot which side of the arrow something is on, but all the things on the left and all the things on the right of the arrow can be in any order you like.

Answer 14

ohh . Okay then. Thanks!