Consider a t distribution with 26 degrees of freedom. Compute P(-1.43 < t < 1.43). Round your answer to at least three decimal places. Consider a t distribution with 12 degrees of freedom. Find the value of c such that P(t ≥ c) = 0.05. Round your answer to at least three decimal places.
Are you using software or t-tables to find the probabilities?
all i have is a TI-83 calculator app on my phone lol.
for the first question, i did tcdf(-1.43,1.43,26) and got 0.835 when rounded to three places.
ya that looks good \(\checkmark\)
Not sure how to do the second one.
Well of that one I know you can use a t-table for that, since 0.05 is an exact probability value found in such a table. I'm not exactly sure what function you can use on your calculator to do it :S
http://bcs.whfreeman.com/ips6e/content/cat_050/ips6e_table-d.pdf Since \(P(t \ge c)=0.05\) is the same as the upper tail probability p, you can look for the critical value in the table at 12 degrees of freedom
1.782?
Oh i figured it out on the calculator, it gave me -1.782 (when rounded) :)
hm it should just be 1.782
-.1782 will give you P(t>c)=0.95 instead of 0.05
-1.782*
oh.. well shoot. so much for my epiphany haha.
lol. Unfortunately I don't have that calculator so I'm not too sure what button you should press? lol.
that's okay I'm sure that the answer is 1.782 :)
I had done something silly on the calculator haha. Thank you for all your help!
:) alright then, your welcome
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