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OpenStudy (anonymous):
How many grams of NH3 are needed to provide the same number of molecules as in 0.15g of SF6
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OpenStudy (anonymous):
There are the same number of molecules in equal numbers of moles, so: (0.15 g) / (146.0554 g SF6/mol) x (17.03056 g NH3/mol) = 0.017 g NH3
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