Question

PLEASE HELP ME

Answer 1

Identify the vertex for the graph of y = 2x^2 + 8x - 3.

(2, 21)

(2, 17)

(-2, -11)

(-2, -27)

Answer 2

I like how Ess was in first place when I was tagged ;)

Ess's got this

Answer 3

@tHe_FiZiCx99 @esshotwired

Answer 4

Too late </3

Answer 5

There. Bt=etter? ^^

Answer 6

The vertex of a parabola y = a(x - h)\(\sf ^2\) + k is at (h, k).

Answer 7

Can you set up the quadrattic in that form first?

Answer 8

No. I have no clue

Answer 9

i think it is B. not completely sure though

Answer 10

Better than nothing! Lol thanks

Answer 11

Well Chris, ma friend, can you explain why you think it's B? Then you would know for sure ;P

Answer 12

Solve x^2 - 8x - 20 = 0.

x = 4, x = -5

x = -4, x = 5

x = 2, x = -10

x = -2, x = 10

Answer 13

factor

Answer 14

Just graph it.. the solutions or roots are found when the parabola intersects the x-axis. Use demos.

Answer 15

C.

Answer 16

aww, you're making his HW so easy

Answer 17

y = 2x^2 + 8x - 3,
set y=0,
0=x^2+4x-3/2
0=(x+2)^2-11/2,
so when x=-2, the point is at the vertex ,
and x=-2,y=8-16-3=-11,
(-2,-11) is the answer

Answer 18

Thanks for the clarification @WilliamZhang

Answer 19

For the graph below, what should the domain be so that the function is at least 300?

graph of y equals minus 2 times the square of x plus 50 times x plus 300

x ≥ 0

-5 ≤ x ≤ 30

0 ≤ x ≤ 25

all real numbers