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How to calculate the Foci w/ the following equation: in comment box
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\[\frac{ y^2 }{ 49} + \frac{ x^2 }{ 25 }\]
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I got (0, +/- 2* sqrt 6 for the foci. c^2 = 49 - 25 c^2 = 24 --> sqrt 4 * sqrt 6 ---> +/- 2* sqrt 6
I assume it is (y/7)^2+(x/5)^2=1. Then, since 7>5 and coordinates with y, so foci are on the Y axis. a=7,b=5,c=sqrt(a^2-b^2)=2sqrt(6). So you are right, the foci are (0,2sqrt(6)) and (0,-2sqrt(6))
@WilliamZhang my equation is = to 1
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