Question

help

Answer 1

What you're doing here is combining to make it look like the f(x) = whatever function.
Your first step is to find the common denominator so you can combine it into one BIG fraction. Here's a hint: \(\sf \{x^2+2x-3 = (x+3)\color{red}{(x-1)}\). As you can see, you already have a (x-1) on the left hand side of the original function.

So, get a common denominator.

Answer 2

i already did that, i ended up with the wrong answer

Answer 3

Can you show me what you did?

Did you get this far: \(\large\sf \frac{3(x+3)}{(x+3)(x-1)}- \frac{12}{(x+3)(x-1)}\) at \(least\)?

Answer 4

Oh, I didn't see the \(x\) on the far right!! Sorry! But it should be: \(\large\sf \frac{x[(x+3)(x-1)]}{(x+3)(x-1)}+\frac{3(x+3)}{(x+3)(x-1)}- \frac{12}{(x+3)(x-1)}\)

Answer 5

but when you simplify that you get
x^3+2x^2-3 divided by (x+3)(x-1)

Answer 6

but that isnt the right answer and there is no way to simplify it further to get that answer

Answer 7

3 12
f(x)= x + ------ - ------------
x - 1 x^2 +2x -3


3 12
f(x) = x + ------- - -------------
x - 1 (x - 1)(x + 3)

x(x-1)(x+3) +3(x+3) -12
f(x) = -------------------------
(x-1)(x+3)

x(x-1)(x+3) +3(x+3 -4)
f(x) = -----------------------
(x-1)(x+3)

x(x-1)(x+3) +3(x-1)
f(x) = -----------------------
(x-1)(x+3)

(x-1)(x(x+3) +3)
f(x) = -----------------
(x-1)(x+3)

x^2 +3x +3
f(x) = ---------------
x + 3

hope so much that this will help you understanding

Answer 8

THANKYOU SO MUCH!