As in the previous problem, the height of a object thrown straight up is given by
y(t) = 100t − 16t2
with y in feet and t in seconds. Compute the average velocity on each of the intervals in the table below. Answers should be accurate to two decimal places.
The correct formula is:
(100(2+h)-16(2+h)^2)-(100(2)-16(2)^2) / (2+h)-2

h -.02 Interval [1.98,2]
I plug in the numbers (100(2+2)-16(2+2)^2)-(100(1.98)-16(1.98)^2) hit enter 8.7264 then divide by .02 and get 436.32 ft/s. However this is showing as incorrect, What am I doing wrong?

Question

As in the previous problem, the height of a object thrown straight up is given by
y(t) = 100t − 16t2
with y in feet and t in seconds. Compute the average velocity on each of the intervals in the table below. Answers should be accurate to two decimal places.
The correct formula is:
(100(2+h)-16(2+h)^2)-(100(2)-16(2)^2)  / (2+h)-2 

h -.02 Interval [1.98,2]
I plug in the numbers (100(2+2)-16(2+2)^2)-(100(1.98)-16(1.98)^2) hit enter 8.7264 then divide by .02 and get 436.32 ft/s. However this is showing as incorrect, What am I doing wrong?

anonymous · Answer

That should be y(t) = 100t-16t^2

joannablackwelder · Answer

What does h represent in your formula?