Question

help plz i will post question best answer will recieve medal and fan

Answer 1

Michelle and Maggie are at baseball practice. Michelle throws a ball into the air and when it drops to a height of 5ft., she hits the ball. The height of the ball is modeled by the graph below where t = time in seconds and h = height of the ball from the ground.

A graph of a parabola is shown. The y-intercepts are at approximately negative 0.1, 0 and 2.1, 0. The vertex is located at the approximate coordinate of 1, 22.

Maggie is throwing a ball into the air and catching it. The height of Maggie’s ball is modeled by the function h(t) = –16t2 + 48t + 15.

Part 1. Which ball goes higher in the air, the ball that is hit or the ball that is thrown? Use complete sentences and show all work to explain how you determined the height that each ball reaches.

Part 2. Determine which girl is likely to be standing on a raised platform. Use complete sentences to explain how you determine which girl is on the platform and then determine the height of the platform.

Part 3. Which ball is traveling at a faster average rate of change on the way up? Use complete sentences to explain how you determined the interval at which the height of the ball is increasing and the average rate of change.

Answer 2

i will put graph now

Answer 3

u can forget this part in question 'A graph of a parabola is shown. The y-intercepts are at approximately negative 0.1, 0 and 2.1, 0. The vertex is located at the approximate coordinate of 1, 22.'

Answer 4

you should get a medal for ur question.

Answer 5

lol thx

Answer 6

but ive been stuck on it for a while now

Answer 7

your question will take minimum 4-10 minutes only for reading..!!!

Answer 8

i have patience I just need help so I can wait

Answer 9

From the graph, you can see that the max height of the ball is about 22 feet and is reached at t = 1 second. Do you see that part?

Answer 10

In order to find the max height of the one from the equation, you are going to have to complete the square. Do you know how to do that?

Answer 11

\[y=-16t ^{2}+48t+15\]First thing to do is to put parenthesis around the t terms, like this:\[y=(-16t ^{2}+48t)+15\]

Answer 12

ok im following u right now

Answer 13

Now complete the square on the t terms, as follows:\[y=-16(t ^{2}-3t)+15\]\[y=-16(t ^{2}-3t+\frac{ 9 }{ 4 }-\frac{ 9 }{ 4 })+15\]\[y=-16(t ^{2}-3t+\frac{ 9 }{4 })+(-\frac{ 9 }{ 4 })(-16)+15\]\[y=-16(t-\frac{ 3 }{ 2 })^{2}+36+15\]and finally\[y=-16(t-\frac{ 3 }{ 2})^{2}+51\]

Answer 14

This means that at approximately t = 1.5 seconds, the ball's max height was reached, which is 51 feet.

Answer 15

If you don't know how to complete the square, none of that will make sense. If you do, just study it closely and carefully and it should all come together.

Answer 16

Thank you if I need help later can I ask u

Answer 17

@IMstuck

Answer 18

@IMStuck

Answer 19

Um..I am going to work, unfortunately now. But I will be back tomorrow and maybe later tonight. TY for the medal!

Answer 20

no thank you