If measurements of gas are 50L and 300K and then the gas is measured a second time and found to be 75L ,describe what happen to the temperature ( if pressure remained constant) . V1=50L,T1300Kpa,V2=75L,T2=?

Question

anonymous · Answer

I know the law of Charles but I'm confuse if I need to dived or multiply 
V1=50L,   T1=300kpa, V2=75L, T2=?

joannablackwelder · Answer

Substitute your values into charles law and solve for T2.

anonymous · Answer

what values,..  how I would put it in equation? 300Kpa - ?

joannablackwelder · Answer

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