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Chemistry 14 Online
OpenStudy (anonymous):

If measurements of gas are 50L and 300K and then the gas is measured a second time and found to be 75L ,describe what happen to the temperature ( if pressure remained constant) . V1=50L,T1300Kpa,V2=75L,T2=?

OpenStudy (anonymous):

I know the law of Charles but I'm confuse if I need to dived or multiply V1=50L, T1=300kpa, V2=75L, T2=?

OpenStudy (joannablackwelder):

Substitute your values into charles law and solve for T2.

OpenStudy (anonymous):

what values,.. how I would put it in equation? 300Kpa - ?

OpenStudy (joannablackwelder):

|dw:1409524665783:dw|

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