Question

Mary invested $12000.00 and got 1% profit in fund a! fund b she made 6% her total profit was 3% how much did she invest in fund b

Answer 1

It's just a translation problem.

a + b = 12000
a*0.01 + b*0.06 = 12000*0.03

Answer 2

Which you can therefore make it to0.01a+0.06b=360

Answer 3

From the wording of the problem, I don't understand if the $12,000 was the investment only in fund A or if the $12,000 was the total investment in funds A and B.

Answer 4

The problem said the investment for fund a was 12000.00 it did not give an amount for fund b. just said she earned 6% profit And the total profit for both funds was 3%

Answer 5

Wow!

12000*0.01
b*0.06
(12000+b)*0.03

Go!

Answer 6

Finally asked for the solution and they said $6,000 was the amount of fund b. have no idea how to get that answer

Answer 7

Since the problem can be interpreted as $12,000 being only for Fund A or for the total of both funds, I solved it both ways below.

Let's call the amount invested in Fund A, a, and the amount invested in Fund B, b.

1. If the total amount invested is $12,000

a + b = 12000
a = 12000 - b

Interest from Fund A Interest from Fund B Total Interest
0.01(12000 - b) + 0.06b = 0.03(12000)

When you solve for b, you get b = 4800
That means the money invested in Fund B is $4800

2. If the entire $12,000 was invested in Fund A, and additional money was invested in Fund B

Interest from Fund A Interest from Fund B Total Interest
0.01(12000) + 0.06b = 0.03(12000 + b)

When you solve for b, you get b = 8000.
That means the money invested in Fund B is $8000

I don't see how you get $6000 invested in Fund B.