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Physics 13 Online
OpenStudy (anonymous):

You are driving through town at 12 m/s when suddenly a ball rolls out in front of you. You apply the brakes and begin slowing down at 3.2 m/s2. When you have traveled half of the distance required to stop, what is your speed?

OpenStudy (anonymous):

Are you familiar with the equations for motion in a straight line with constant acceleration ?

OpenStudy (anonymous):

Kind of? I worked it out and got 72 m/s, which doesn't make sense

OpenStudy (anonymous):

hmm, you're right, that doesn't make sense

OpenStudy (anonymous):

There might be different ways to solve this problem, but I have an idea what you need to do

OpenStudy (anonymous):

Okay

OpenStudy (anonymous):

Any idea what is the first thing you need to try to calculate ?

OpenStudy (anonymous):

I calculated the total distance and got 22.5 m

OpenStudy (anonymous):

Right, total distance is a good place to start, i haven't calculated it yet - which formula did you use ?

OpenStudy (anonymous):

Vf^2= Vi^2+ 2ax

OpenStudy (anonymous):

yes, that's what i've got, i make it 22.5 so now what's the halfway point in distance ?

OpenStudy (anonymous):

11.25- I plugged it back in and got 72 for some reason

OpenStudy (anonymous):

ok wait, you're doing it correctly but just look carefully at the formula that you plug back into

OpenStudy (anonymous):

what does that formula calculate ?

OpenStudy (anonymous):

you already wrote it out for me a few lines ago : )

OpenStudy (anonymous):

oh my god. V^2.

OpenStudy (anonymous):

: )

OpenStudy (anonymous):

take the square root and you're in business

OpenStudy (anonymous):

Wow, I feel like an idiot. Thank you!

OpenStudy (anonymous):

no problem - and don't feel like an idiot, that's the way most stuff gets done, with some back and forth, looking for the errors !

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