Need some help on a couple of math problems and could use some help and explaining please :)
1. (3x^2)^2
2. (7y^4)^2
3. xy^3z^-1 over x^2yz
4. y^2z over x^2yz^-3

Question

Need some help on a couple of math problems and could use some help and explaining please :)
1. (3x^2)^2
2. (7y^4)^2
3. xy^3z^-1 over x^2yz
4. y^2z over x^2yz^-3

anonymous · Answer

do you know know overall how to do these problems?

anonymous · Answer

not really thats why i asked for someone to help explain them to me :)

anonymous · Answer

true true the first answer is (3x^2)^2

anonymous · Answer

now try to figure out how i got that, tell me what u thinkin

anonymous · Answer

3:
$$\large \frac{xy^3z^{-1}}{x^2yz}$$ maybe easiest if you bring the $z^{-1}$ in to the denominator and start with$$\large \frac{xy^3}{x^2yz^2}$$

anonymous · Answer

How can the first answer be the question asked? Does it not need to be simplified

anonymous · Answer

sorry autocorrect, its 9x^4

anonymous · Answer

@alex1248191  that was the question 
$$(3x^2)^2$$ it is not really a question, it is an expression but i think they want you to square each term and get 
$$3^2x^4=9x^4$$

anonymous · Answer

I get it. @daydreamer just multiply by the power of two for each one.

anonymous · Answer

exactly @satellite73

anonymous · Answer

so what you did is squared all of it? so 3 * 3 =9 and then 2 * 2=4 okay i get it! It just clicked!!

anonymous · Answer

Yay! (:

anonymous · Answer

you square the first number, the you add both of the exponents together

anonymous · Answer

you don't square the exponents, (that mistake is comkonly made) you add them together

anonymous · Answer

oh okay that is noted most defiantly :)

anonymous · Answer

Nice! thats very important

anonymous · Answer

$$3\sqrt{2}+\sqrt{8}$$ could you help with this last one :) @alex1248191