Question

y(y-3) -0 solve for y!

Answer 1

it should be =0 not minus

Answer 2

Is that all to the equation? Is there another side of the equation. y(y-3)-0=?

Answer 3

Ah ok.

Answer 4

Start by distributing the y.

Answer 5

so y^2 - 3y=0

Answer 6

Yes

Answer 7

okay

Answer 8

@Dscdago are you still there?

Answer 9

Yes. I'm trying different ways to solve this. And at the same time writing it in here.

Answer 10

ohh okay thank you! I thought you left haha

Answer 11

You can maybe apply the quadratic formula. You have y^2-3y+0=0. \[\frac{ -(-3)\pm \sqrt{(-3)^{2}-4(1)(0)} }{ 2(1) }\]\[\frac{ -(-3)\pm \sqrt{(9)-0}}{ 2 }\]\[\frac{ -(-3)\pm \sqrt{9} }{ 2 }\]\[\frac{ -(-3)\pm 3 }{ 2 }\]\[\frac{ -(-3) + 3 }{ 2 }=\frac{ 3+3 }{ 2 }= \frac{ 6 }{ 2 }=3\]\[\frac{ -(-3)-3 }{ 2 }=\frac{ 3-3 }{ 2 }=\frac{ 0 }{ 2 }=0\]

The solutions for the problem is y=0,3.
Sorry it took long, I had a problem in my math and had to correct it.

Answer 12

Oh my gosh! Thank you so so much!!!!

Answer 13

No problem. Glad I could help.