Algebra 2. Fan and Medal
question?
lol you want us to do it for you
why not?
No. You dont have to. I just didnt understand it and I need help.
to find the equation of the line between the points \((0,3)\) and \((1,2)\) you need the slope
so i would use y=mx+b?
right one, down one means the slope is \(-1\) since it goes through the point \((0,3)\) you know the \(y\) intercept is \(3\) making your equation \[y=-x+3\]
yes, \(y=mx+b\) with \(m=-1,b=3\)
oh damn they said "standard form" hold the phone
so it would look like y=(-1)x+3?
\[y=-x+3\\ x+y=3\] second one is standard form
yes, it is \(y=(-1)x+3\) but if you write it that way, displaying the \(-1\) your teacher will think you are an idiot, so don't do it, just write \(y=-x+3\) then change it to \(x+y=3\)
lol alright. Sorry I suck at math D:
yeah its okay just don't put a 1 or a -1 in front of anything wanna do the second one?
Yes please
points are \((0,3)\) and \((-3,0)\) slope is \[\frac{3-0}{0-(-3)}=\frac{3}{3}=1\]
again the point \((0,3)\) tells you the \(y\) intercept is \(3\) so write \[y=mx+b\] with \(m=1,b=3\)
but whatever you do, do not write \[y=\color{red}1x+3\] just write \[y=x+3\]
thank you
yw might as well finish them right? \[(-3,0),(-1,-4)\] slope is \[\frac{0-(-4)}{-3-(-1)}=\frac{4}{-2}=-2\]
this time you do not know the \(y\) intercept so you have to use the point - slope formula \[y-y_1=m(x-x_1)\] with \[x_1=-3,y_1=0, m=-2\]
y-0=-2(x--3) ?
yes, now lets clean it up
\[y=-2(x+3)\] would be the first step then distribute the \(-2\) to finish
you should end up with \[y=-2x-6\] hope this was more or less clear finding the equation of a line given two points is not too hard and a decent skill to have
You helped me alot. Gave me a better understanding. Thank you so much :)
yw
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