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OpenStudy (anonymous):
\[\frac{ 6\sqrt{3} }{ -9+\sqrt{6} }\]
OpenStudy (dangerousjesse):
What do you need to do with this? The simplified version would simply be \(\large\frac{6\sqrt 3}{\sqrt6 - 9}\)
OpenStudy (anonymous):
Well, I have to simplify it
OpenStudy (perl):
it looks pretty simple to me
OpenStudy (perl):
it looks simple to me already
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OpenStudy (dangerousjesse):
Ah.. Easy peasy ;D
OpenStudy (perl):
jess, whats dangerous about you
OpenStudy (perl):
mathlete sounds gay, i need to change this
OpenStudy (dangerousjesse):
Hahaha, everything.
OpenStudy (anonymous):
So, would i multiply the numerator and denominator by the denomenator
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OpenStudy (anonymous):
- 18 square root 3/25-6 square root 2/25
OpenStudy (anonymous):
how'd u do that
OpenStudy (anonymous):
\[\frac{ 6\sqrt{3} }{ \sqrt{6}-9 } = \frac{ 6\sqrt{3} }{ \sqrt{2}\sqrt{3}-\sqrt[4]{3} }\]
Simplifies to
\[\frac{ 6 }{ \sqrt{2}-3\sqrt{3} }\]
Actually, just multiply the numerator and denominator by the denominator and see what you get