Given any two polyhedra of equal volume, is it always possible to cut the first into finitely many polyhedral pieces which can be reassembled to yield the second?
I said no If P is cut into two polyhedral pieces P1 and P2 with one plane cut, then \(D(P) = D(P1) + D(P2).\) If P is cut into n polyhedral pieces \(P1,...,Pn\), then \( D(P) = D(P1) + ... + D(Pn)\)
Et cetera
(I cheated, I just want to know if it's accurate)
are you reading a solution manual?
what does this mean "If P is cut into two polyhedral pieces P1 and P2 with one plane cut, then "
No, I'm using Wiki http://en.wikipedia.org/wiki/Hilbert%27s_third_problem#Dehn.27s_answer
haha, never copy paste what you do not understand
i can demand an explanation and call your bluff
It's extra credit.. I understand none of this, or at least very little ;P
join the club dangerous Jess
just dont pretend to be in 'that' club, people who understand the article
its like pretending to have climbed mount everest
yeah, it was pretty cold
Eh, I remember that seventh day. Colder than the first.
sorry i didnt mean to be rude, i was being wry
this hat is not sold in most stores
Join our real-time social learning platform and learn together with your friends!