Please help i have no idea where to even begin on this inequality

Question

mikezack123 · Answer

$$26+6b \ge 2(3b+4)$$

shadowlegendx · Answer

Inequalities, those were fun

mikezack123 · Answer

lol i wish it was fun to me :)

anonymous · Answer

$$26+6b \ge 2(3b+4)$$ divide all by 2 and start with 
$$13+3b\geq 3b+4$$

anonymous · Answer

combine like terms

anonymous · Answer

then subtract $3b$ from both sides and see that 
$$13\geq 4$$which is always true

shadowlegendx · Answer

13 is greater than or equal to 4 c;

anonymous · Answer

oh these tricky math teachers 
they are so amusing
anyway, this inequality is always true no matter what $b$ is

mikezack123 · Answer

Thank you very much @satellite73

anonymous · Answer

yw

mikezack123 · Answer

wait I'm kind of confused as to why are we getting rid of the variable. aren't we supposed to keep it?

anonymous · Answer

it just happens to go away when you subtract it from both sides

anonymous · Answer

if you had 
$$2b+4\geq b+1$$ you would subtract $b$ from both sides and you would still have one left 
$$b+4\geq 1\
b\geq-3$$

anonymous · Answer

but since you have $3b$ on both sides, they go bye bye

mikezack123 · Answer

so were not solving for the variable?

shadowlegendx · Answer

Farewell $$3b$$ you will be missed

shadowlegendx · Answer

@MikeZack123 you are solving the inequality, not the variable

mikezack123 · Answer

got it, thank you @ShadowLegendX