Question

I need help with solving an equation for indicated variables, if someone could help me and check my work, that would be awesome!

Answer 1

#1 \[p = \frac{ w }{ t } \] for w

#2 \[P = \frac{ w }{ t } \] for t

Answer 2

@ganeshie8

Answer 3

There are more complicated ones than this >.>

Answer 4

#3 \[E = \frac{ 9R }{ I }\]

Answer 5

for I

Answer 6

what do you get for 1 and 2?

Answer 7

tp = w

wp = t

>.>

Answer 8

1 is correct
2 is not

Answer 9

Yeah I'm so confused with these >.<

Answer 10

I know I have to get the indicated variable alone, but I don't know how >.<

Answer 11

t = w/p

Answer 12

So those are the answers, but I want to know how to solve these! They're so hard but I want to learn them

Answer 13

when you have an equation such as
a = b/c OR

a/b = c/d

you can do something that is called cross-multiplying

Answer 14

if p = w/t then if we multiply both sides by t we get pt = w
then we divide both sides by p and we get t = w/p

Answer 15

The second one is w = t/p

Answer 16

Is that correct?

Answer 17

no w = pt

If p = w/t then we multiply both sides by t and we get w=pt

Answer 18

do you follow?

Answer 19

Oh ok

Answer 20

so what's your guess for no. 3

Answer 21

9RE = I

Answer 22

Oh and btw I have to state a property or explain each step for how I solved #3

Answer 23

each step

Answer 24

If E=9R/I then we multiply both sides by I and we get EI = 9R
Then we divide both sides by E and we get I = 9R/E

Answer 25

do you get it now?

Answer 26

Ok, yeah

#4

ak - r = on

For k

I got k = on/a + r

Answer 27

Hard, but starting to make a lil sense

Answer 28

I did #4 like 20min ago, so it may or may not be correct

Answer 29

First you add r to both sides

Answer 30

ak = on + r

Answer 31

Then isolate k right?

Answer 32

that's it. then you divide both sides by a

Answer 33

\[k = \frac{ on + r }{ a }\] ???

Answer 34

beautiful!! you do get it!

Answer 35

;3

Answer 36

I just have 5 more of these to do xD

Answer 37

ok

Answer 38

Which shows the equation

\[c = a \left(\begin{matrix}w \\ 150\end{matrix}\right)\]

correctly solved for the variable w?

A. w = a(150c)

B. w = a(c/150)

C. w = 150/ac

D. w = 150c/a

Answer 39

D!

Answer 40

Yes it's D

Answer 41

#35

w = gm

Solve for m

#36

Q = 1/2P + 15

Solve for P

#37 I = V/R

Solve for R

#38

y = mx + b

Solve for m

Answer 42

Let me do those real quick ;3

Answer 43

#35 w/g = m

#36 Tricky one

\[\frac{ 2 }{ 1 } \times Q - 15 = p \]

#37 IV = R

#38 \[\frac{ y-b }{ x } = m\]

Answer 44

#35 is correct

Answer 45

#36 is close. P = 2(Q-15)

Answer 46

Oh just simplify the 2/1 to a 2?

Answer 47

#37 R = V/I

Answer 48

my teacher is really weird about fractions, sometimes he just says to leave them in that form and he knows you understand it. So I think he might take 2/1

Answer 49

and #38 is right!!

Answer 50

But simplifying it does make it more clear c;

Answer 51

that's fine. for #36 you can go P=(2/1) x (Q-15)
but it's normally expressed as I first wrote it

Answer 52

well done!!

Answer 53

i hope you have a better understanding of algebraic manipulation

Answer 54

Ok I changed #36, it was a simple error and I understand it now :) Thanks so much, I wish I could give you a million medals >.>

Answer 55

You've been here with me for like a whole hour :P

Answer 56

Thank you so much!

Answer 57

If you don't mind me asking, what grade are you?

Answer 58

I'm a high school tutor

Answer 59

Cool ;3

Answer 60

I'm solving this problem now

\[2.80 = \frac{ 9(70) }{ I }\]

Answer 61

In baseball, the equation

\[E = \frac{ 9R }{ I }\]

gives a pitchers run average E, where R is the number of earned runs the player allowed and I is the number of innings pitched.

Last season, a pitcher had earned run average of 2.80 and allowed 70 earned runs. how many innings did the pitcher pitch last season?