Question

a ball is dropped from a tower. when it lands, its velocity is 30 m/s g=10 m/s^2. how long does it take for the ball to hit the ground?

Answer 1

Here,
Final velocity = 30 m/s
In case of dropping, initial velocity = 0 m/s
acceleration = 10 m/s


We have to find time taken, we can use the equation v = u+at
=> 30=0+10\(\sf \times t\)
=>t = 3 seconds

Answer 2

Got it ?

Answer 3

Yes thank you so much! I'm so thankful....

Answer 4

My pleasure :)

Answer 5

you divided the velocity with the g=10 m/s^2 right? to get 3 seconds?

Answer 6

yes

Answer 7

okay! thanks I still have more questions :) i need to post

Answer 8

Ok go ahead, post it as a new one :)