Solve for the equation and state the solution
Any solution, no solution, one solution, zero solution
OpenStudy (anonymous):
@PRAETORIAN.10
OpenStudy (anonymous):
\[\frac 34 t - \frac 23 t = -\frac 56\]
\[\implies t(\frac 34 - \frac 23) = -\frac 56\]
\[\huge\implies t = -\frac{\frac 56}{\frac 34 - \frac 23}\]
solve that and you have t
OpenStudy (anonymous):
I don't understand the thought process behind the modeling you did for this equation
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OpenStudy (mathmath333):
easy way is to take LCM of denominators 4,6 and 3 and multiply the whole equation with the LCM
OpenStudy (anonymous):
So convert the denominators into 12?
OpenStudy (mathmath333):
yes absolutely
OpenStudy (anonymous):
Yeah I get
9/12t + 10/12 = 8/12t
OpenStudy (mathmath333):
now multiply and divide (10/12) with t
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OpenStudy (anonymous):
I'm not sure what you mean...do 10/12 * t ?
OpenStudy (mathmath333):
all denominators except the 10/12 doesn't have t
OpenStudy (mathmath333):
\[10/12=10t/12t\]
OpenStudy (mathmath333):
like the above
OpenStudy (mathmath333):
then all the denominators will be the same and will be cancelled
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OpenStudy (anonymous):
Seems kinda weird to just pull out a t and slap it on a number out of the blue, haha, maybe that's just c;
OpenStudy (mathmath333):
it saves time ,lol
OpenStudy (anonymous):
19/12t = 8/12t
OpenStudy (anonymous):
?
OpenStudy (mathmath333):
\[3t/4 +5/6=2t/3\]
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OpenStudy (anonymous):
Yeah
9/12t + 10/12 = 8/12t
OpenStudy (mathmath333):
\[9t/12 +10/12=8t/12\]
OpenStudy (anonymous):
Then we multiplied 10/12 by t, to get 10/12t
OpenStudy (anonymous):
For work shown, I just did 9/12t + (t) 10/12 = 8/12t to show that I multiplied t with 10/12
OpenStudy (anonymous):
to get 10/12t
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OpenStudy (mathmath333):
here if we multiply by 12 to both sies all the denominator will be canceled
OpenStudy (mathmath333):
sry
OpenStudy (mathmath333):
look at the equation now
OpenStudy (mathmath333):
\[9t+10=8t\]
OpenStudy (anonymous):
To make it 9t + 10 =8t
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OpenStudy (mathmath333):
\[9t -8t+10=0\]
OpenStudy (mathmath333):
yes
OpenStudy (anonymous):
1t + 10 = 0
OpenStudy (mathmath333):
i think u can calulate {t} easily now
OpenStudy (anonymous):
or just t
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