Question

maximum value of
sin^2(120+Q)+sin^2(120-Q)

Answer 1

uhhhh what math is this!!???

Answer 2

trigonometry

Answer 3

oh dang i havnt taken this!

Answer 4

trigonometry means too confusion.

Answer 5

not an issue guys.. i will try to solve it. Thanks

Answer 6

i am sorry @sachin

Answer 7

Have you tried rewriting it first in some other way

Answer 8

I would probably start by using sum and difference identities for sin
then square the result
then see some things cancel
then write in terms of one trig function

Answer 9

it cant exceed 2

Answer 10

have a hunch that when Q = 0 thats the max.

Answer 11

@tylerd for some reason that would work but I don't know why.

Answer 12

same

Answer 13

I found the same answer doing the whole rewriting thing

Answer 14

So it was just a hunch @TylerD
Any clue why that works?

Answer 15

plugged in some values and noticed the closer it got to q=0, the higher the value. if you go backward it gets smaller then eventually comes full circle. or something like that.

Answer 16

Ah. Limits.

Answer 17

but i suppose q could also equal 360 or -360?

Answer 18

well I know it is
I won't show exactly how I rewrote it
But I will tell you I wrote sin some form where you have
B-Asin^2(theta)
where A and B are some constants I would like @sachin.davra to obtain himself
Then I thought of what would be sin^2's min since we are subtracting there
And if for some reason you had found A to be negative then you would actually find the sin^2's max.
Then add.

Also look that some expression and had fun with some calculus giving me the same result

Answer 19

hint: both A and B >0

Answer 20

sin's max is 1
sin^2's max is also 1

Answer 21

may have something to do with sin^2x+cos^2x=1 where sin(90-x)=cos(x)

Answer 22

sin^2's min is 0

Answer 23

But sachin.davra posted this like 18 hours ago
he is probably no longer here

Answer 24

oh wow, says hes here though maybe afk.

Answer 25

i suck at it too so if anyone could help as well that would be great http://openstudy.com/updates/5404b92de4b0f2ed1e146373

Answer 26

1.)for maximum value of sine function u have to make it 90 degree
so try to first make \[120+Q=90\] first which will be when \[q=-30\]
then also put \[q=-30\] in the second sine function \[120-Q\] .
calculate the result .
2.)now make \[120-Q=90\] which will come when u take \[Q=30\]
and also put the value \[Q=30\] in first sine function \[120+Q\]
calculate the result.



u will find both the result to be same and hence will be the maximum value