TWO PARTICLES A AND B START FROM REST AND MOVE FOR EQUAL TIME ON A STRAIGHT line . THE PARTICLE A HAS AN ACCELERATION A FOR THE FIRST HALF OF THE TOTAL TIME AND 2A FOR THE SECOND HALF . THE PARTICLE B HAS AN ACCELERATION 2A FOR FIRST HALF AND A FOR SECOND HALF . WHO HAS COVER A LARGER DISTANCE .
@Mashy
You answer in mathematics
no.. its not supposed to be in math :P
or here is ok whatever u wish
I am getting same for both of them
btw , i used 2nd equation of motion
ok.. so lets use our stomach, (intuition) first tell me this if you have two objects A and B A starts from rest.. and B is having 5m/s velocity and suppose they both accelerate with acceleration, a for some time t which one covers more distance? A or B ? don't do math.. just use logic
B covers more
Precisely .. because B already had a velocity to begin with..
yess!!
so if we compare the motion of A and Bnow in your question A first accelerates with a for first half and during that half, B accelerates with 2a clearly B travels more.. (infact twice the distance compared to a, in that half time) and now what u can see is car B ends up with a velocity which is TWICE that of car A so now for the rest half, car B accelerates with a, and car accelerates with 2a but since car B has this advantage of having TWICE THE SPEED TO BEGIN WITH.. (i mean beginning of second half), B will travel more.. can u see that?
Deep thinking there , i got the point
my instinctive reaction was both travel same distance ,
ok now lets do this mathematically together.. and confirm this shall we? how much distance did A and B travel in the first half? (we will call this time as t)
B has a greater initial velocity to begin with the nexy half
next*
precisely!!
its that part.. that gives B the advantage ;-)
YEs i would love to see that mathematically
How would we do that
for A intial velocity u = 0 time t = t acceleration = a so u can calculate distance s for B intial velocity u = 0 time t= t acceleration = 2a so find distance for A and B .. this will be for the first half
YES
do it :P
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