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OpenStudy (anonymous):

How many atoms of hydrogen are present in the reactants and in the products?

OpenStudy (frostbite):

Same equation as before?

OpenStudy (anonymous):

yep, we gotta use the same equation 4 questions 1-3

OpenStudy (frostbite):

Sure so we have: 6CO2 + 6H2O → C6H12O6 + 6O2 So now we want the atoms not the molecules like before. So I want to take a super fast example with another molecule before you start. The following molecule is ethanol and I want you to try tell me how many hydrogen there is in it: C2H6O

OpenStudy (anonymous):

6

OpenStudy (frostbite):

Perfect. What if I wrote: 2 C2H6O

OpenStudy (anonymous):

6 again?

OpenStudy (frostbite):

Yeah this is the tricky part. If we write a number in front of a chemical we mean that chemical that number of times. So for example: 2 C2H6O would be 12 hydrogen 3 C2H6O would be 18 hydroge and so on.

OpenStudy (frostbite):

Somehow understandable?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so what now?

OpenStudy (frostbite):

Good. Now then lets return to real question: 6CO2 + 6H2O → C6H12O6 + 6O2 How how many hydrogen do we got on both sides?

OpenStudy (anonymous):

14... i think

OpenStudy (frostbite):

Close, but not correct try again.

OpenStudy (anonymous):

12?

OpenStudy (frostbite):

Exactly. :)

OpenStudy (anonymous):

ha

OpenStudy (frostbite):

Not that hard so far huh? :)

OpenStudy (anonymous):

gonna open a new question

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