Question

What is the standard form of the equation of a circle with its center at (2, -3) and passing through the point (-2, 0)?

Answer 1

(x+h)^2 + (y-k)^2 = r^2

where r is the radius
x and y are points
h and k are the center x and y coordinate

Answer 2

first of all sketch it on some axes:



The 2 points are on my diag - add the circle

One is the centre, one is ON the circle - so the distance between them is the radius
What is that distance?

Answer 3

wait so how do I get the distance?

Answer 4

@larryboxaplenty that is not correct

the distance between the centre and the point is the radius.

Use Pythagoras to find the radius