A circle is described by the equation (x-1/2)^2+(y-3/2)^2=4/9. What are the cordinates for the center of the circle and the length of the radius?

A)(-1/2,-3/2), 2/3units

B) (-1/2,-3/2), 4/9units

C) (1/2,3/2), 4/9units

D) (1/2,3/2), 2/3units

Question

A circle is described by the equation (x-1/2)^2+(y-3/2)^2=4/9. What are the cordinates for the center of the circle and the length of the radius?

A)(-1/2,-3/2), 2/3units

B) (-1/2,-3/2), 4/9units

C) (1/2,3/2), 4/9units

D) (1/2,3/2), 2/3units

anonymous · Answer

plz explain

mrnood · Answer

you have shown in the last two questions we tackled that you already know how to do this.

the formula is (x-a)^2+(y-b)2 = r^2

(a,b) is the centre.

Just look at the equation you have.

It is easy to get a and b from the 'brackets'

r is simple sqrt(right hand side)....

You CAN do this

anonymous · Answer

so is it b?

mrnood · Answer

and sqrt(m/n) = sqrt(m)/sqrt(n) which makes it very easy to get the value for the radius....

mrnood · Answer

PLEASE do not guess.

You can do this.

I do not confirm or deny whether your guess is correct.