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Hyperbola equation?
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I have never done this :3
This is a y^2 hyperbola. The asymptotes are of the nature \[y=\pm \frac{ a }{ b }\]The general form of the hyperbola is\[\frac{ (y-k)^{2} }{a ^{2} }-\frac{ (x-h)^{2} }{ b ^{2} }=1\]So if the asymptotes are a over b, take the a, square it, and put it under the (y-k)^2 and take the b, square it, and put it under the (x-h)^2.
a = 5 then and b = 4
If a = sq rt 5, and b = 2, then a^2 is 5 and b^2 is 4, so the hyperbola equation is this:\[\frac{ y ^{2} }{ 5 }-\frac{ x ^{2} }{ 4 }=1\]
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It's choice A. Not too bad, right?
TY for the medal!
ah I know now...thank you!! Not bad at all...good help :)
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